3.353 \(\int \frac {(c \sin (a+b x))^m}{(d \cos (a+b x))^{3/2}} \, dx\)

Optimal. Leaf size=77 \[ \frac {\sqrt [4]{\cos ^2(a+b x)} (c \sin (a+b x))^{m+1} \, _2F_1\left (\frac {5}{4},\frac {m+1}{2};\frac {m+3}{2};\sin ^2(a+b x)\right )}{b c d (m+1) \sqrt {d \cos (a+b x)}} \]

[Out]

(cos(b*x+a)^2)^(1/4)*hypergeom([5/4, 1/2+1/2*m],[3/2+1/2*m],sin(b*x+a)^2)*(c*sin(b*x+a))^(1+m)/b/c/d/(1+m)/(d*
cos(b*x+a))^(1/2)

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Rubi [A]  time = 0.06, antiderivative size = 77, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.043, Rules used = {2577} \[ \frac {\sqrt [4]{\cos ^2(a+b x)} (c \sin (a+b x))^{m+1} \, _2F_1\left (\frac {5}{4},\frac {m+1}{2};\frac {m+3}{2};\sin ^2(a+b x)\right )}{b c d (m+1) \sqrt {d \cos (a+b x)}} \]

Antiderivative was successfully verified.

[In]

Int[(c*Sin[a + b*x])^m/(d*Cos[a + b*x])^(3/2),x]

[Out]

((Cos[a + b*x]^2)^(1/4)*Hypergeometric2F1[5/4, (1 + m)/2, (3 + m)/2, Sin[a + b*x]^2]*(c*Sin[a + b*x])^(1 + m))
/(b*c*d*(1 + m)*Sqrt[d*Cos[a + b*x]])

Rule 2577

Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[(b^(2*IntPart
[(n - 1)/2] + 1)*(b*Cos[e + f*x])^(2*FracPart[(n - 1)/2])*(a*Sin[e + f*x])^(m + 1)*Hypergeometric2F1[(1 + m)/2
, (1 - n)/2, (3 + m)/2, Sin[e + f*x]^2])/(a*f*(m + 1)*(Cos[e + f*x]^2)^FracPart[(n - 1)/2]), x] /; FreeQ[{a, b
, e, f, m, n}, x]

Rubi steps

\begin {align*} \int \frac {(c \sin (a+b x))^m}{(d \cos (a+b x))^{3/2}} \, dx &=\frac {\sqrt [4]{\cos ^2(a+b x)} \, _2F_1\left (\frac {5}{4},\frac {1+m}{2};\frac {3+m}{2};\sin ^2(a+b x)\right ) (c \sin (a+b x))^{1+m}}{b c d (1+m) \sqrt {d \cos (a+b x)}}\\ \end {align*}

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Mathematica [A]  time = 0.09, size = 78, normalized size = 1.01 \[ \frac {\sqrt [4]{\cos ^2(a+b x)} \tan (a+b x) \sqrt {d \cos (a+b x)} (c \sin (a+b x))^m \, _2F_1\left (\frac {5}{4},\frac {m+1}{2};\frac {m+3}{2};\sin ^2(a+b x)\right )}{b d^2 (m+1)} \]

Antiderivative was successfully verified.

[In]

Integrate[(c*Sin[a + b*x])^m/(d*Cos[a + b*x])^(3/2),x]

[Out]

(Sqrt[d*Cos[a + b*x]]*(Cos[a + b*x]^2)^(1/4)*Hypergeometric2F1[5/4, (1 + m)/2, (3 + m)/2, Sin[a + b*x]^2]*(c*S
in[a + b*x])^m*Tan[a + b*x])/(b*d^2*(1 + m))

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fricas [F]  time = 0.59, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {d \cos \left (b x + a\right )} \left (c \sin \left (b x + a\right )\right )^{m}}{d^{2} \cos \left (b x + a\right )^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))^m/(d*cos(b*x+a))^(3/2),x, algorithm="fricas")

[Out]

integral(sqrt(d*cos(b*x + a))*(c*sin(b*x + a))^m/(d^2*cos(b*x + a)^2), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (c \sin \left (b x + a\right )\right )^{m}}{\left (d \cos \left (b x + a\right )\right )^{\frac {3}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))^m/(d*cos(b*x+a))^(3/2),x, algorithm="giac")

[Out]

integrate((c*sin(b*x + a))^m/(d*cos(b*x + a))^(3/2), x)

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maple [F]  time = 0.10, size = 0, normalized size = 0.00 \[ \int \frac {\left (c \sin \left (b x +a \right )\right )^{m}}{\left (d \cos \left (b x +a \right )\right )^{\frac {3}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*sin(b*x+a))^m/(d*cos(b*x+a))^(3/2),x)

[Out]

int((c*sin(b*x+a))^m/(d*cos(b*x+a))^(3/2),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (c \sin \left (b x + a\right )\right )^{m}}{\left (d \cos \left (b x + a\right )\right )^{\frac {3}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))^m/(d*cos(b*x+a))^(3/2),x, algorithm="maxima")

[Out]

integrate((c*sin(b*x + a))^m/(d*cos(b*x + a))^(3/2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (c\,\sin \left (a+b\,x\right )\right )}^m}{{\left (d\,\cos \left (a+b\,x\right )\right )}^{3/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*sin(a + b*x))^m/(d*cos(a + b*x))^(3/2),x)

[Out]

int((c*sin(a + b*x))^m/(d*cos(a + b*x))^(3/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (c \sin {\left (a + b x \right )}\right )^{m}}{\left (d \cos {\left (a + b x \right )}\right )^{\frac {3}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))**m/(d*cos(b*x+a))**(3/2),x)

[Out]

Integral((c*sin(a + b*x))**m/(d*cos(a + b*x))**(3/2), x)

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